数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an-n)是等比数列,求an
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/21 09:18:22
数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an-n)是等比数列,求an数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an
数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an-n)是等比数列,求an
数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an-n)是等比数列,求an
数列an满足a1=-1,且an=3a(n-1)-2n=3,求a2,a3,并证明数列(an-n)是等比数列,求an
a2=3a1-2+3=-2,a3=3a2-4+3=-7.
an=3a(n-1)-2n+3,则an-n=3an-3n+3,即an-n=3[a(n-1)-(n-1)].而a1-1=-2.
所以,数列{an-n}是首项为-2、公比为3的等比数列,其通项为an-n=-2*3^(n-1).
所以,an=n-2*3^(n-1)(n为正整数).
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足a(n+1)=an+3n+2,且a1=2,求an=?
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an
已知数列an满足a(n+1)=an+3n+2,且a1=2,求an
已知数列{an}满足3a(n+1)=2an-4,且a1=1/5,求an
已知数列{an}满足条件a1=3,且a( n+1)-an=(20)^n+n,求通项公式已知数列{an}满足条件a1=3,且a( n+1)-an=(2)^n+n,求通项公式
已知数列{an}满足a1=4/3,且an+1=4(n+1)an/3an+n
数列[An]满足a1=2,a(n+1)=3an-2 求an
已知数列an满足an=4a(n-1)+3n-4,且a1=3,证明数列an+n为等比数列
数列{an]满足a1=1且an+1=an+3n次方,求an通项公式
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an
数列证明题一题设数列{An}满足:A1=1,且当n∈N*时,An^3+An^2×[1-A(n+1)]+1=A(n+1)求证:数列{An}是递增数列.
已知数列{an}满足a1=3,且a(n+1)-3an=3的n次方(n属于N*)求通项an
在数列{an}中.a1=3且a(n+1)=an^2,求an
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an
已知数列{an}满足:an+1=an+n,且a61=2002,则a1等于
根据下列条件,确定数列{an}的通项公式1.在数列{an}中,a(n+1)=3an^2,a1=32.在数列{an}中,a1=2,a(n+1)=4an-3n+13.在数列{an}中,a1=8,a2=2,且满足a(n+2)-4a(n+1)+3an=0
已知数列{an}满足a1=1,且an=3a(n-1)+2^(n-1),证明{an+2^n}是等比数列