定义：unsigned int a=013,b=0x13,c;执行后c=~a|b>>3；后,c的值是这个该怎么计算呢

unsigned int gcd(unsigned int a,unsigned int b){while(b^=a^=b^=a%=b);return a;} unsigned char ctoa(char a[]){unsigned char c=0;for(int i=0;i 定义：unsigned int a=013,b=0x13,c;执行后c=~a|b>>3；后,c的值是这个该怎么计算呢 c语言中,delay的意思在c语言中定义一个delay（）函数void delay_ms(unsigned intT){unsigned int CON;unsigned int i;for(i=0;i *( *)这个定义类型怎么理解PLLA_toPLLV_sel = *((volatile UINT32*)(0x88210004))；asm_back = *(unsigned int *)DEF_ASM_BACK；#define reset (*(unsigned int *)RESET)；这些定义是什么意思！要怎么理解！做了哪些的赋值或操 main( ) {unsigned int a=3,b=10; printf(%d/n,a1); } 已知：unsigned int=3,b=10;printf(%d ,a 求补码怎么求的...#include #include void main (){unsigned short int a;unsigned short int getbits(unsigned short);printf ( input an octal number:);scanf (%o,&a);printf (%o ,getbits(a));}unsigned short int getbits (unsigned short value){u 设有如下的变量定义:int i =8,k ,a,b ; unsigned long w=5; double x=1.42,y=5.2; 则以下符合C语言.设有如下的变量定义:int i =8,k ,a,b ; unsigned long w=5; double x=1.42,y=5.2; 则以下符合C语言语法的表达式是：（A）a+ #include main() {unsigned int a=65535; printf(a=%d ,a); } 运算结果 a=-1#includemain(){unsigned int a=65535;printf(a=%d ,a);}运算结果a=-1为什么是等于-1呢? unsigned char a[4] = {0,0,0,1};int b = *((int*)a); 这样执行完毕后,b的值是多少?unsigned char a[4] = {0,0,0,1};int b = *((int*)a);这样执行完毕后,b的值为什么不是1,而是16777216,而unsigned char a[4] = {0,0,0,0}; b的值就可 求解main(){unsigned a=32768;int b;b=a;printf(b=%d ,b);} void delayms(uint j){uchar i;for(;j>0;j--){i=250;while(--i);i=249;while(--i);}有几个宏定义忘记写了,现在补上.#define uchar unsigned char#define uint unsigned int#define out P2 void delay(unsigned int time){unsigned int j=0;for(;time>0;time--)for(j=0;j 关于LZW算法int find_match(int hash_prefix,unsigned int hash_character){int index;int offset;index = (hash_character 晕啊,下面的程序定义怎么理解啊bit RW24xx(unsigned char *DataBuff,unsigned char Length,unsigned int Addr,unsigned char Control,enum eepromtype enumer)特别是那个enum eepromtype enumer；第一次见这种形式的枚举的定义啊, #include stdio.hvoid main(void){ int a=10; int *p = &a; unsigned int b = (unsigned int)p; printf(0x%x ,p); printf(0x%x ,b); int *out = (int *)b; printf(0x%x , *out);} 很奇怪,只能打印前两个printf,最后一个 连求什么都不知.一、填空：(1) 以下程序的输出结果是 【1】　　main()　　{ unsigned short a=65536; int b;　　printf(“%d ”,b=a) ;　　}(2) 若有定义：int a=10,b=9,c=8; 接着顺序执行下列语句后,变量b中的