y=(x-1)^2,x=0,y=0,x=2围成的图形绕y轴旋转一周所产生的旋转体的体积,我知道绕x轴怎么算,可这是绕y轴,求详解sorry,是曲线y=(x-1)^2

设x大于1,y大于0,x^y+x^-y=2根号二,x^y-x^-y等于? x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 mathematica软件,已知y[x],Y=f1(x),X(x)=f2(x),如何plot Y[X]?y[x_] := x + 9.81/2*x*xk=1X[x] = x - k*y'[x]/(1 + (y'[x])^2)^0.5Y[x] = y[x] + k/(1 + (y'[x])^2)^0.5Plot[{y[x],Y[X],},{x,0,2}] （x+y-5)*（x+y-5)+（x-y+3)=0 x*x-y*y 已知:3x-5y=0,求x/y,x-y/y,x-y/x 已知x,y满足约束条件：x-y+1>=0,x+y-2>=0,x x*x+2x+y*y-4y+5=0 x= y= 已知x>0,Y>0,如何证x^2/y+y^2/x>=x+y 设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y y=1/x^2(x>0) y=(1-x)/(1+x) y=(e^x-e^-x)/2 y=1-x^2 x>=0 ,y=sin|x|/x x 若x+y=1,x不等于0则x+(2xy+y^2)/x/(x+y)/x= 若|x+y-1|+（x-y-2)²=0,求代数式（x+2y)(x-2y）-（2x-y)(-y-2x)的值. 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) 已知x^2+y^2-8x+12y+52=0 ,求1/2x-1/x-y(x-y/2x-x^2+y^2) {4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? 变量x,y满足x-2y=0,x