数列{an}满足a1=1,an=1/2an-1+1(n≥2)求an通项式~
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/28 13:20:00
数列{an}满足a1=1,an=1/2an-1+1(n≥2)求an通项式~数列{an}满足a1=1,an=1/2an-1+1(n≥2)求an通项式~数列{an}满足a1=1,an=1/2an-1+1(
数列{an}满足a1=1,an=1/2an-1+1(n≥2)求an通项式~
数列{an}满足a1=1,an=1/2an-1+1(n≥2)
求an通项式~
数列{an}满足a1=1,an=1/2an-1+1(n≥2)求an通项式~
令bn=an-2
an-2=1/2an-1-1=1/2(an-1-2)
∴(an-2)/(an-1-2)=1/2
即bn/bn-1=1/2
又有a1=1 b1=-1
∴{bn}为首项b1=-1,公比是1/2的等比数列
bn}通项公式为bn=-(1/2)^(n-1)
带入bn=an-2得 an=2-(1/2)^(n-1) (n≥2)
a=1时不成立 此时a1=1
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列{an}满足a1=a,an+1=1+1/an.若3/2
数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
数列[An]满足a1=2,a(n+1)=3an-2 求an
数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an满足a1=2,an+1=4an+9,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列an满足a1=2,an+1=an²求an
数列an满足a1=2,an+1=an²求an
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=?
数列{an}满足a1=2,a(n+1)=-1/(an+1),则a2010等于
数列{an}满足a1=3,a n+1=2an,则a4等于
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
已知数列{an}满足a(n+1)=an+lg2,a1=1,求an