函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少
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函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少y
函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少
函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少
函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少
y=sin(x-π/3)+cos(π+x+π/6)
=sin(x-π/3)-cos(x+π/6)
=sin(x-π/3)-sin[π/2-(x+π/6)]
=sin(x-π/3)-sin(π/3-x)
=sin(x-π/3)+sin(x-π/3)
=2sin(x-π/3)
所以最小值=-2
y=sin(x-π/3)+cos(x+7π/6)=1/2sinx-根号3/2cosx-根号3/2cosx+1/2sinx
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