化简求值已知X+Y+Z=0 ,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/25 21:59:03
化简求值已知X+Y+Z=0,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值化简求值已知X+Y+Z=0,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+
化简求值已知X+Y+Z=0 ,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值
化简求值
已知X+Y+Z=0 ,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值
化简求值已知X+Y+Z=0 ,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值
x+z=-y
x+y=-z
所以y²+z²-x²
=y²+(x+z)(z-x)
=y²-y(z-x)
=y(y-z+x)
=y(-z-z)
=-2yz
同理
z²+x²-y²=-2zx
x²+y²-z²=-2xy
原式=-1/2*(1/xy+1/yz+1/xz)
=-1/2*(x+y+z)/xyz
=0
化简求值已知X+Y+Z=0 ,求(1/Y2+Z2-X2)+(1/Z2+X2-Y2)+1/X2+Y2-Z2)的值
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
哪位帅哥美女能帮忙解这道代数式化简求值的练习题?已知x-y=a,z-y=10,求代数式x×x+y×y+z×z-xy-yz-zx
化简求值4x-{2x+3[x+2(4z-x)-2y]-7y}+6z其中x-y=-3,y-z=-1
已知x.y.z满足/x-2/+(y+3)^2=0,z是最大的负整数.化简求值:2(x^y+xyz)-3(x^2y-xyz)-4x^y
已知 (x+y-z)/z=(x-y+z)/y=(y+z-x)/x,且xyz≠0,求代数式 ((x+y)(y+z)(x+z))/xyz
分式加减法:已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
已知X+Y+Z=0,求(X+Y)(Y+Z)(X+Z)+XYZ的值.
已知x+y+z=0,求(x+y)(y+z)(z+x)+xyz的值
已知x+y+z=0,求(x+y)(y+z)(x+z)+xyz的值
已知x+y+z=0,求代数式x(1/y+1/z)+y(1/x+1/z)+z(1/x+1/y)的值需详细的化简过程在线等,速求,Thx
化简求职:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²化简求值:(2x-y+3z)(-2x-y-3z)-(x+2y-3z)²,其中x=1,y=-1,z=1
已知{2x-y-z=0,3x-9y+z=0求1,x:y:z
已知4x-3y-3z=0 x-3y-z=0 (1)求x:y:z
已知(1)X-Y+Z=0 (2)X+2Y-3Z=0 求X:Y:Z