数列满足a1=1 an=2an-1-3n+6 设bn=an-3n 求证bn是等比数列
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数列满足a1=1an=2an-1-3n+6设bn=an-3n求证bn是等比数列数列满足a1=1an=2an-1-3n+6设bn=an-3n求证bn是等比数列数列满足a1=1an=2an-1-3n+6设
数列满足a1=1 an=2an-1-3n+6 设bn=an-3n 求证bn是等比数列
数列满足a1=1 an=2an-1-3n+6 设bn=an-3n 求证bn是等比数列
数列满足a1=1 an=2an-1-3n+6 设bn=an-3n 求证bn是等比数列
因为an=2an-1-3n+6
所以an-3n=2[an-1-3(n-1)]
即bn=2bn-1
因为a1=1,故b1=a1-3=-2不等于0
所以bn是等比数列,公比是2
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