不等式组1-2分之x≥0和x+2>-2分之1的负整数解是
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不等式组1-2分之x≥0和x+2>-2分之1的负整数解是
不等式组1-2分之x≥0和x+2>-2分之1的负整数解是
不等式组1-2分之x≥0和x+2>-2分之1的负整数解是
1-x/2≥0
x+2>-1/2
1≥x/2
x>-5/2
2≥x
x>-5/2
所以2≥x>-5/2
所以负整数解为-2,-1
①得，x≤2
②得，x﹥-5/2
∴不等式组的解集：
﹣5/2﹤x≤2
∴负整数解; -2、-1、
From 1-x/2>=0 we can see that 2-x>=0, x<=2.
From x+2>-1/2 we can see that x>-2.5
The question requires x to be negative integer, we can work out that x=-2 or -1
It's embarrassing that the ...
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From 1-x/2>=0 we can see that 2-x>=0, x<=2.
From x+2>-1/2 we can see that x>-2.5
The question requires x to be negative integer, we can work out that x=-2 or -1
It's embarrassing that the computers in my school don't have the language of Chinese, so I can't answer in Chinese. Hope there's no limitation for you to get my point.
Anyway, would you please accept my answer? For I worked hard on this!
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-2 -1