sin^2(π/4 +x)
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sin^2(π/4+x)sin^2(π/4+x)sin^2(π/4+x)sin^2(π/4+x)=[1-cos2(π/4+x)]/2=[1-cos(π/2+2x)]/2=1/2+sin2x/2运用公式
sin^2(π/4 +x)
sin^2(π/4 +x)
sin^2(π/4 +x)
sin^2(π/4 +x)
=[1-cos2(π/4 +x)]/2
=[1-cos(π/2 +2x)]/2
=1/2+sin2x/2
运用公式
Cos2A=CosA^2-SinA^2=1-2SinA^2
sin^2(π/4 +x)
=[1-cos(π/2+2x)]/2
=[1-(cosπ/2cos2x-sinπ/2sin2x)]/2
=[1-(0-sin2x)]/2
=(1/2)sin2x+1/2
这种单有平方的,一般就用二倍角公式,即将原式化为与(π/2 +2x)的关系,通过Cos2A=1-2SinA^2,代入原式即得cos2A,解得为 (1+sin2x)/2
2sin(x+π/4)sin(x-π/4)=?
sin^2(π/4 +x)
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sin(x+π/4)
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