求y=sin(2x+π/6)x∈(0,π/3)的值域
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求y=sin(2x+π/6)x∈(0,π/3)的值域求y=sin(2x+π/6)x∈(0,π/3)的值域求y=sin(2x+π/6)x∈(0,π/3)的值域y=sin(2x+π/6)x∈(0,π/3)
求y=sin(2x+π/6)x∈(0,π/3)的值域
求y=sin(2x+π/6)x∈(0,π/3)的值域
求y=sin(2x+π/6)x∈(0,π/3)的值域
y=sin(2x+π/6)
x∈(0,π/3)
2x∈(0,2π/3)
2x+π/6∈(π/6,5π/6)
y∈(1/2,1]
x∈(0,π/3)
2x+π/6∈(π/6,5π/6)
则:
y∈(1/2,1]
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