设f(x)=sin(2x+ π/6 )+2msinxcosx,x∈R.当m=0时,求f(x)在[0,π/3]内的最小值及相应的x的值;
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设f(x)=sin(2x+π/6)+2msinxcosx,x∈R.当m=0时,求f(x)在[0,π/3]内的最小值及相应的x的值;设f(x)=sin(2x+π/6)+2msinxcosx,x∈R.当m
设f(x)=sin(2x+ π/6 )+2msinxcosx,x∈R.当m=0时,求f(x)在[0,π/3]内的最小值及相应的x的值;
设f(x)=sin(2x+ π/6 )+2msinxcosx,x∈R.
当m=0时,求f(x)在[0,π/3]内的最小值及相应的x的值;
设f(x)=sin(2x+ π/6 )+2msinxcosx,x∈R.当m=0时,求f(x)在[0,π/3]内的最小值及相应的x的值;
m=0
f(x)=sin(2x+π/6)
0=
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