已知如图,AB=AC,AD=AE,角BAC=角DAE,试说明BD=CE的理由

如图,已知AD/DB=AE/EC,求证 :AD/AB=AE/AC. 已知:如图,AC/AD=AB/DE=BC/AE.求证AB=AE 已知,如图,AD/AC=DE/AB=AE/BC,求证AB=AE 已知,如图,AD:AC=DE:AB=AE:BC 求证：AB=AE 如图,已知：AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证：ED⊥BC. 已知:如图,角BDA=角CEA,AE=AD.求证:AB=AC 已知如图,AD/AE=AB/AC,求证角B=角ADE 已知:如图,AD/AB=AE/BC求证：AD/AE=DB/EC和AB/DB=AC/EC 已知:如图,AD/AB=AE/BC求证：AD/AE=DB/EC和AB/DB=AC/EC 如图,DE//BC,请问AD:AC=AE:AB?AD:AE=AB:AC? 已知如图AB=AC AD=AEBE与CD相交于点P求证pc=pb已知 如图,AB等于AC,AD等于AE,BE与CD相交于点P 1.求证PC等于PB2.求证角CAP等于角BA 已知：如图,AB＝AC,AD＝AE,BE与CD相交于点P.1.求证PC＝PB.2.求证∠CAP＝∠BAP.3 已知如图AB=AC,求证AB²=AD×AE 已知:如图,在△ABC中,AB=AC,延长BA至点D,使AD=AB,连接CD,AE是△ACD的高.求证:AE‖BC 如图,△ABC中AB⊥AC,且AB=AC,点E在AC上,点D在BA的延长线上,AD=AE.如图,△ABC中AB⊥AC,且AB=AC,点E在AC上,点D在BA的延长线上,AD=AE.已知,△ADC与△AEB全等.猜想并说明BE和CD有何特殊的关系.【要引辅助线,但 如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证：AC=EF. 已知,如图AB=AC,AD=AE,LBAC=LDAE,求证：LB=LC 已知；如图,ab=ac,bd=ce,ad=ae.求证be=cd. 全等三角形如图,已知AB=AC,AD=AE,求证BD=CE.