已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=
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已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=已知数列{an}满足a1=5,a(n+1)=an+6n+6,则a
已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=
已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=
已知数列{an}满足a1=5,a(n+1)=an+6n+6,则an=
a(n+1)=an+6n+6
所以a(n+1)-an=6n+6
所以
a2-a1=6*1+6
a3-a2=6*2+6
a4-a3=6*3+6
...
an-a(n-1)=6(n-1)+6
叠加得an-a1=6[1+2+...+(n-1)]+6(n-1)=3n(n-1)+6(n-1)=3n²+3n-6
因为a1=5
所以an=3n²+3n-6+a1=3n²+3n-1
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