已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是( ).{7y-2(x-y)=10

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/22 19:48:31
已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是().{7y-2(x-y)=10已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是().{7y-2(x-y)=10已知

已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是( ).{7y-2(x-y)=10
已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是( ).{7y-2(x-y)=10

已知x、y满足方程组{7x+6(x-y)=130,则x--y的值是( ).{7y-2(x-y)=10
7x+6(x-y)=130.1
7y-2(x-y)=10 .2
1式-2式得
7(x-y)+4(x-y)=120
11(x-y)=120
x-y=120/11

7x+6(x-y)=130
7y-2(x-y)=10
两式相减:7(x-y)+8(x-y)=120
x-y=8