若f(sinx)=3-cos2x,则f(cosπ/6)=

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若f(sinx)=3-cos2x,则f(cosπ/6)=若f(sinx)=3-cos2x,则f(cosπ/6)=若f(sinx)=3-cos2x,则f(cosπ/6)=f(cosπ/6)=f(sinπ

若f(sinx)=3-cos2x,则f(cosπ/6)=
若f(sinx)=3-cos2x,则f(cosπ/6)=

若f(sinx)=3-cos2x,则f(cosπ/6)=
f(cosπ/6)
=f(sinπ/3)
=3-cos(2×π/3)
=3-(-1/2)
=7/2

f(cosπ/6)= f(sinπ/2-π/6)=f(sinπ/3)=3-cos2*π/3=3+0.5=3.5

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