f(sinx)=3-cos2x,则f（cosx）=
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f(sinx)=3-cos2x,则f（cosx）=f(sinx)=3-cos2x,则f（cosx）=f(sinx)=3-cos2x,则f（cosx）=f(sinx)=3-cos2x=3-[1-2(si
f(sinx)=3-cos2x,则f（cosx）=
f(sinx)=3-cos2x,则f（cosx）=
f(sinx)=3-cos2x,则f（cosx）=
f(sinx)=3-cos2x=3-[1-2(sinx)^2]=2+2(sinx)^2,即f(sinx)=2+2(sinx)^2把其中的sinx换成cosx,得
f(cosx)=2+2(cosx)^2=cos2x+3
f(sinx)=3-cos2x = 3 - [1-2(sinx)^2] =2+2(sinx)^2
即f(x)=2+2x^2，则f(cosx)=2+2(cosx)^2 = 3+cos2x，因 2(cosx)^2 - 1= cos2x
f(sinx)=3-cos2x
cos2x=1-2sin^2(x)
f(sinx)=3-1+2sin^2(x)=2+2sin^2(x)
f(x)=2+2x^2
f(cosx)= 2+2cos^2(x)
f(sinx)=3-cos2x=3-(1-2(sinx)^2)令SINX=t,则f(t)=3-(1-2t^2)=2t^2-2,再令COSX=T,f(t)=2cos^2t-2
如果f(sinx)=3-cos2x,则f(cos2x)等于多少?题目是cos2x,不是cosx
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