int i,n,t=1;double s=0,d; scanf("%d",&n); for(i=1;i
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inti,n,t=1;doubles=0,d;scanf("%d",&n);for(i=1;iinti,n,t=1;doubles=0,d;scanf("%d",&n);for(i=1;iinti,n
int i,n,t=1;double s=0,d; scanf("%d",&n); for(i=1;i
int i,n,t=1;double s=0,d; scanf("%d",&n); for(i=1;i
int i,n,t=1;double s=0,d; scanf("%d",&n); for(i=1;i
正常应该输出1.0
如果想按你设想的输出正确结果,就将d = 1 / t;修改为d = 1.0 / t;
因为d=1/t在t > 1时, d = 0;所以s一直等于1
int i,n,t=1;double s=0,d; scanf(%d,&n); for(i=1;i
怎么求值啊?#include double f(int n){int i;double s;s=1.0;for(i=1;i
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