int i,n,t=1;double s=0,d; scanf("%d",&n); for(i=1;i

int i,n,t=1;double s=0,d; scanf(%d,&n); for(i=1;i 怎么求值啊?#include double f(int n){int i;double s;s=1.0;for(i=1;i 以下函数是计算多项式_____的值double f(int n){ double i,t=1,s=t;for(i=2;i 填空题给定程序中,函数fun的功能是：计算下式前n项的和作为函数值返回.s=1*3/2*2+3*5/4*4+5*7/6*6+.+(2*n-1)*(2*n+1)/(2*n)(2*n).#include 　　double fun(int n)　　{ int i; double s, t;　　//　　s=s+(2.0*i-1)*(2.0*i+1)/__ #include int main(){inti,n=20;double a=2,b=1,s=0,t;for(i=1;i #includedouble fun(double q){int n;double s,t;n=2;s=2.0;while(s 递归二分发求方程解#include using namespace std;double f(double t){return t*t*t-3*t+4;}double b(double a,double b,int n){double t=(a+b)/2;if(n==1||f(t)==0){return t;}if(f(a)*f(t)>x>>y;cin>>c;double s=b(x,y,c);cout 这个C++梯形法求定积分的函数为什么错了double tixing(double (*f)(double),double a,double b){int n=1000,i;double s,sum=0,d;d=(b-a)/n;double y1=(*f)(a+i*d);double y2=(*f)(a+i*d-d);for (i=1;i c语言编程.计算级数前n项的和：1+x+x*x/2!+x*x*x/3!+...+x的n次方/n!.我的编程哪里错了请指点一下.#includedouble f(int n,double x){int i;double y=k=s=t=1;for(i=1;i #include double fun( int m ){double t = 1.0;int i;for( i = 2; i syntax error :identifier 'n'#includeint i,n,s;int proone(int i,n,s=0);int protwo(int i,n,s=0);void main( ){double s1,s2;int m,n;cout 输入1 个正整数n,计算 s 的前n项的和(保留 4 位小数).s = 1 + 1/2! +.+ 1/n! 要求定义并调用函数fact(n)计算n的阶乘.#include stdio.hint main( ){ int ri,repeat; int i,n; double s; double fact(int n); scanf(%d,&repeat) 用高斯法求解方程int rgauss(int n,double a[],double b[]){int *js,l,k,i,j,is,p,q;double d,t;js=(int *)malloc(n*sizeof(int)); //开辟用于记忆列交换信息的动态空间l = 1; //置非奇异标志for(k=0;k 1.请问 while(n--)是怎样运行的?这可以作为判断的条件吗?2.s += i / int main(){int n;double i,j,k;double s = 0;scanf(%d,&n);i= 1;j = 1;while(n--){k = i;i = k + j;j = k;s += i / j;}printf(%.4f ,s);return 0;} 计算圆周率的C语言程序#include int main (){int n;double s=1.0;for (n=1;n 一个简单编程题#include#includeint main(){int n,i=1,m=1;double x,s=0;scanf(%d%d,&x,&n);while(i 寻找程序（计算1+2!+3!+.）错误.#include #include main() { int j,i,n; do#include#includemain(){int j,i,n;double s,sum;scanf(%d,&n);sum=0;for(i=1;i for ( ; i ^ 1; i >>= 原程序完整代码如下：# include # include # define N 100005int n,D;int cnt[4 * N],num[N];void update(int i){for ( ; i ^ 1; i >>= 1){cnt[i >> 1] = cnt[i] + cnt[i ^ 1];}}int query(int s,int t){int ret;ret = 0;s += D-1,t +=