[(x-3)/2]/(x+1)=49%这个方程咋解
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 01:57:20
[(x-3)/2]/(x+1)=49%这个方程咋解[(x-3)/2]/(x+1)=49%这个方程咋解[(x-3)/2]/(x+1)=49%这个方程咋解[(x-3)/2]/(x+1)=49%(x-3)/
[(x-3)/2]/(x+1)=49%这个方程咋解
[(x-3)/2]/(x+1)=49%这个方程咋解
[(x-3)/2]/(x+1)=49%这个方程咋解
[(x-3)/2]/(x+1)=49%
(x-3)/2=49%(x+1)
(x-3)/2=0.49x+0.49
x-3=0.98x+0.98
x-0.98x=0.98+3
0.02x=3.98
x=199
(x-3)/2(x+1)=49/100 => (x-3)/(x+1)=49/50=>50x-150=49x+49 => x=199...ans
[(x-3)/2]/(x+1)=49%
(x-3)/2=0.49(x+1)
x-3=0.98(x+1)
x-3=0.98x+0.98
x-0.98x=3+0.98
0.02x=3.98
x=3.98/0.02
x=199
(X+1)X(X+2)X(X+3)=504
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)
x(x-2)-2x(x+1)-3x(x-5) 其中x=负½
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2)...(x-49)等于多少?
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
(x+1)/(x+2)+(x+8)/(x+9)解答x+1/x+2+x+8/x+9=x+2/x+3+x+7/x+8
七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X.
=(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+25x^2+10x^2-50x+24 这是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24
判断下列函数是否具有奇偶性?【1】:f(x)=x+x³这一个我会做解:函数的定义域为R,x∈R,有-x∈Rf(-x)=(-x)+(-x)³ =-x-x³ =-(x+x³) =-f(x)【2】h(x)=x³+1【3】f(x)=(x+1)(x-1)【4】h(x)=