如图,AB=AC,角1=角2=角3,求证:BD=CE

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如图,AB=AC,角1=角2=角3,求证:BD=CE如图,AB=AC,角1=角2=角3,求证:BD=CE 如图,AB=AC,角1=角2=角3,求证:BD=CE∵∠1=∠2∴∠1+∠CAD=∠

如图,AB=AC,角1=角2=角3,求证:BD=CE
如图,AB=AC,角1=角2=角3,求证:BD=CE
 

如图,AB=AC,角1=角2=角3,求证:BD=CE
∵∠1=∠2
∴∠1+∠CAD=∠2+∠CAD
即∠BAD=∠CAE
∵∠1+∠B+∠ACB=180°
∠3+∠ACE+∠ACB=180°
∠1=∠3
∴∠B=∠ACE
∵∠BAD=∠CAE,AB=AC,∠B=∠ACE
∴△ABD≌△ACE
∴BD=CE