化简sin^4x-sin^2+cos^2化简(1)sin^4x-sin^2+cos^2(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)
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化简sin^4x-sin^2+cos^2化简(1)sin^4x-sin^2+cos^2(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)化简sin^
化简sin^4x-sin^2+cos^2化简(1)sin^4x-sin^2+cos^2(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)
化简sin^4x-sin^2+cos^2
化简(1)sin^4x-sin^2+cos^2
(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)
化简sin^4x-sin^2+cos^2化简(1)sin^4x-sin^2+cos^2(2)根号(1+cosα/1-cosα)+根号(1-cosα/1+cosα)(180°<α<270°)
(1) (sinx)^4 - (sinx)^2 + (cosx)^2
=(1-cos2x)^2/4 + cos2x
= [ 1 - 2 cos2x + (cos2x)^2 + 4 cos2x ] / 4
= ( 1 + cos2x )^2 /4
= [ ( 1 + cos2x ) / 2 ]^2
= (cosx)^4
(1)sin^2x(sin^2x-1)+cos^2x-->sin^2x(-cos^2x)+cos^2x-->cos^2x(1-sin^2x)-->cos^4x
(2) 表达式大于0,所以将表达式平方,表达式^2=(1+cosα)/(1-cosα)+(1-cosα)/(1+cosα)+2=
4/sin^2α,所以表达式=-2/sinα(因为表达式为正,所以前面加-号)
化简sin^4x-sin^2x+cos^2x
化简:sin^4 x-sin^2 x+cos^2 x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简sin^4x+cos^2x
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x
化简 cos^2(x)*sin^2(x)-sin^2(x)
化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x)
化简【完整步骤!】1.(sin^4x-sin^2x)/secx2.sin^4x-cos^4x【这道题的正确答案是sin^2x-cos^2x】
sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简)
化简sin^4x+sin^2xcos^2x+cos^2x=?(请写过程)
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cos^4 x-sin^4 x+2 sin^2 x化简
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sin x cos x cos 2x 化简