设实数X,Y满足约束条件（x-y+2≥0 x+y-3≤0 x≥0 y≥0 求Z=2x+y的最大值=?这种怎么写啊.能告诉我解这题的方法么x-y+2≥0x+y-3≤0x≥0y≥0

设实数x,y满足约束条件：x>=2;y>=x;2x+y 设X,Y满足约束条件X+Y 当实数x,y,满足约束条件{x>0 y>=x 2x+y+k 设x,y满足约束条件x>=0 x>=y 2x-y 实数x,y满足约束条件.求范围实数x,y满足约束条件x-y+2>=0 x+y-4>0x 设实数x和y满足约束条件,x+y≤10,x-y≤2,X≥4,则Z=2x+3y的最小值为? 设变量X,Y满足约束条件{X-Y+3>=0,X+Y>=0,-2 设变量x,y满足约束条件:x-y+3>=0 x+y>=0 -2 若实数x,y满足约束条件x-y-2=0,2y-3 设实数x,y满足线性约束条件x+y=3,y>=0,则目标函数z=2x+y的最大值 已知实数x,y满足约束条件x+y>3,y 设实数x y满足约束条件①x-2y≤0 ②2x-y≥0 ③x2+y2-2x-2y≤0,则目标函数z=x+y的最大值为 若实数x,y满足约束条件x-y≥0,x+y≥0,2x+y≤1,则y/(x+1)的最大值是多少, 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 设变量x,y满足约束条件 {x-y≥0,x+y≤1,x+2y≥0},则函数Z=2x+y 的最大值? 设变量x,y满足约束条件 {x-y≥0,x+y≤1,x+2y≥0},则函数Z=2x+y 的最大值? 已知实数x,y满足约束条件x≥0 y≤x 2x+y-9≤0,则z=x+3y的最大值等于?