lim(0-∞)/(x+1)

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lim(0-∞)/(x+1)lim(0-∞)/(x+1)lim(0-∞)/(x+1)0..

lim(0-∞)/(x+1)
lim(0-∞)<(x^1/3)*cosx>/(x+1)

lim(0-∞)/(x+1)
0..

lim(0-∞)/(x+1) 求极限lim(x→0)sinxsin(1/x);lim(x→∞)(arctanx/x) lim(cos1/n)^n^2 n->∞lim (1+|x|)^1/x x->0 1.lim x->∞ (2x/x^2+1)*cosx 2..lim x->∞{ [(x^2-x)arctanx]/x^3-x-5}3..lim x->0 (e^x-e^-x-2x)/(x-sinx) 4..lim x->0 (sinx-x)/(x^3) 5..lim x->0 (x^2*tanx)/(x-tanx) 6..lim x->0 (1+3/x)^2x 7..lim x->0 (1+2x)^(3/sinx) 8.lim x->∞ (x/1+x)^(x-3) 9..li 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim(1-x)^(2/x) x->0 为什么lim x→∞ sinx/x =0而lim x→0 sinx/x =1? lim(x->0+)(1/x)^tanx lim(x—0) (1-cosx)/x lim(x->0+) e^(1/x) 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)(1-x/2)^1/x+118、求下列函数的间断 用罗必达法则解 (见图)lim [(e^x)-1/sin(5x)]x->0lim [1-cos(5x)/1-cos(7x)]x->0lim x->0 [(8^x-7^x-1)/(x^2)-1]lim [1-(6/x)]^x x->∞ lim 7cos(3x)sec(9x)x->pi/2 当lim(x-->0)(g(x)) = 0 ,证明 lim (x-->0)(g(x)*sin1/x) = 0lim (x-->0)(sin1/x)不是不存在吗? 还有 为什么lim (x-->0)((sinx)/x) = 1? lim (x-->0)((sinx)/x)不是等于lim (x-->0)((1/x)lim (x-->0)((1/x) * lim (x-->0)((sinx))吗? lim (x-->0 10个个极限的运算求解1)lim(x-1)(3次根号下x-1)/(根号x-1)2)lim(x-∞)(x^2+1)^50/(x+1)^1003)lim(x-∞)2x+3/x+3次根号下X4)lim(x-0)sin4x/x5)lim(x-0)1-cos2x/xsinx6)lim(x-∞)[(x-1)/(x+3)]^(x+2)7)lim(x-∞)n[ln(n+3)-l X趋于0 Lim(xlnx)=Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))=Lim(-x)=0Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))其中这步使怎么转化的? lim x→0 sin2x/sin5xlim x→0 (1-cos2x)/x²lim x→0 in(1-x/2)^1/xlim x→∞ (1+2/x)^2x+1lim x→0 sin2x/sin5xlim x→0 (1-cos2x)/x²lim x→0 in(1-x/2)^1/xlim x→∞ (1+2/x)^2x+1lim x→3 (x-3)cos1/(x-3)lim x→0 (e^sinx-e^x)/(sinx-x) lim(x->0) x/sinx=?lim(x->∞) x*sin1/x=? lim(x->1) x^(1/(1-x)) lim(x->0) x^(tanx)的值