(x^2+4x)^2-x^2-4x-20
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(x^2+4x)^2-x^2-4x-20(x^2+4x)^2-x^2-4x-20(x^2+4x)^2-x^2-4x-20(x^2+4x)^2-x^2-4x-20=(x^2+4x)^2-(x^2+4x)
(x^2+4x)^2-x^2-4x-20
(x^2+4x)^2-x^2-4x-20
(x^2+4x)^2-x^2-4x-20
(x^2+4x)^2-x^2-4x-20
=(x^2+4x)^2-(x^2+4x)-20
=[(x^2+4x)-5][(x^2+4x)+4]
=(x+5)(x-1)(x+2)^2
把平方打开
x^4+8*x^3+15*x^2-4*x-20
=(x+5)*(x-1)*(x+2)^2
(x^2+4x)^2-x^2-4x-20
=0.5[(x/2+4x)-x-8x-40]
=0.5(4.5x-9x-40)
=0.5(-4.5x-40)
=-2.25x-20
我猜 ^应该是除号吧
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