若x^2+9y^2-2x+24y+17=0,求x^2与y^2
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若x^2+9y^2-2x+24y+17=0,求x^2与y^2若x^2+9y^2-2x+24y+17=0,求x^2与y^2若x^2+9y^2-2x+24y+17=0,求x^2与y^2x²+9y
若x^2+9y^2-2x+24y+17=0,求x^2与y^2
若x^2+9y^2-2x+24y+17=0,求x^2与y^2
若x^2+9y^2-2x+24y+17=0,求x^2与y^2
x²+9y²-2x+24y+17=0
(x²-2x+1)+(9y²+24y+16)=0
(x-1)²+(3y+4)²=0
x-1=0,3y+4=0
得x=1,y=-4/3
x²=1²=1
y²=(-4/3)²=16/9
若x²+9y²-2x+24y+17=0
那么(x-1)²+(3y+4)²=0
所以x-1=0,3y+4=0
所以x=1,y=-4/3
所以x²=1,y²=16/9
看不懂你的符号
把17分成1的平方和4的平方,再直接配方(x-1)∧2=0;(3y+4)∧2=0,解出方程式就行了,再算x,y各自的平方
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
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