f(x)=﹛x-3 x≥100 f[f(x+5)] x<100﹜ 求f(89)
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f(x)=﹛x-3x≥100f[f(x+5)]x<100﹜求f(89)f(x)=﹛x-3x≥100f[f(x+5)]x<100﹜求f(89)f(x)=﹛x-3x≥100f[f(x+5)]x<100﹜求
f(x)=﹛x-3 x≥100 f[f(x+5)] x<100﹜ 求f(89)
f(x)=﹛x-3 x≥100 f[f(x+5)] x<100﹜ 求f(89)
f(x)=﹛x-3 x≥100 f[f(x+5)] x<100﹜ 求f(89)
因为89<100
所以f(89)=f(f(89+5))=f(94)=f(f(94+5))=f(99)=f(99+5)=f(104)
因为104≥100
所以f(104)=104-3=101
故f(89)=f(104)=101
答案:f(89)=101
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