复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是

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复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是复数Z是纯虚数,则其实部为0,所以:a

复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是
复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是

复数Z=a+(a+1)i(a∈R)是纯虚数,则Z^2是
复数Z是纯虚数,则其实部为0,所以:a=0
Z=i,Z^2=-1.