-m^2+2m=4n-n^2+2n=4m求m和n

(m-n)^2*(m-n)^4=? 已知3m=4n,则m/m+n+n/m-n-m^2/m^2-n^2= (m-2n/n-m)-(n/m-n)= (m-2n)(2n+m)-(-3m-4n)(4n-3m)= m+n/4m^-n^-m-2m/n^-4m^= .4（m+n)^2*（m+n)^3-7（m+n)（m+n)^4+5（m+n)^5= [(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n (n/m+n/2m^2)*4m/n^2 [(m-n)^2*(m-n)^3]^2/(m-n)^4 [(m-n)^2*(m-n)^3]^2/(m-n)^4 4m^2(m+n)-9n^2(m+n) 因式分解4m^2(m-n)+4n(n-m) 4m(m-n)^2+4n(n-m)^3 （m-n)2(n-m)3(n-m)4化简 (m-n)^3(n-m)^2(m-n)=_____ (m-2n)^2+(3m-n)(2m+2n)-(2m+n)(2m-n) 已知m+n=4 mn=1 如果m和n互为相反数,则m+2m+3m+4m+5m+5n+4n+3n+2n+n= 如果m,n互为相反数,求m+2m+3m+4m+5m+5n+4n+3n+2n+n=多少