求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 06:34:27
求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,求lim[x

求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,
求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,

求lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2},答案为2/3,
lim[x趋于无穷]{(x^3)*ln[(x+1)/(x-1)]-2x^2}
=lim[x趋于无穷]{(x^2){xln[(x+1)/(x-1)]-2}
=lim[x趋于无穷]{xln[1+2/(x-1)]-2}/[x^(-2)]
=lim[x趋于无穷]{ln[1+2/(x-1)]+x[1+2/(x-1)]^(-1)[-2/(x-1)^2]}/[-2x^(-3)]
=lim[x趋于无穷]{-2x/(x-1)^2[-2x^(-3)]
=2/3