y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
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y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.y=根号2sin(2x-π)co
y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
sin(2x-π)=-sin(2x)
cos【2(x+π)】=cos(2x)
y=√2sin(2x-π)cos【2(x+π)】
=-√2sin(2x)cos(2x)
=-√2/2 * sin(4x)
=√2/2 * sin(4x+π)
怎么题目上两边都有y啊,右边那个应该是ф吗?
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y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
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