lim(x→∞)x^2+1/x^4+1怎么求极限,

lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 lim x→∞(2x+1)/(3x-4) Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(x^2+x)/(x^4-3x-1)的极限 x/2-1lim(1-2/x)x→∞ lim(x→∞)(1-2/x) (x+1)次方 lim(x→∞)[1+(1/x)]^x/2 lim(x→∞)(1-2/x)^2x lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= 求lim(√x^2+1)-x x→-∞ lim(x→0)(a^2x-1)/4x 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 烦人的数学微积分1、lim(x→0)Sin3x/Sin2x2、lim(x→0)x/3*Sin3x3、lim(x→0)[Xsin(3/x)+(tanx/2x)]4、lim(x→3)Sin(x-3)/(X^2-X-6)5、lim(x→∞)[1+(1/2x)^x6、lim(x→∞)(x+3/x)^x7、lim(x→0)（1-x/2)^1/x+118、求下列函数的间断 求 lim(x→1)sin(x+1)/x+1 求 lim(x→2)x²-4/x-2 lim x→∞(x-1/x+1)^X/2+4