求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)
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求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^
求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)
求值：[log6(3)]^2+log6(18)/log2(6)
[log6(3)]^2+log6(18)/log2(6)
求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)
[log6(3)]^2+log6(18)/log2(6)
=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]
=[log6(3)]^2+2log6(3)log6(2)+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(3*2)]^2
=1
求值:log6^3+log6^2=log6^6为什么?
求值：[log6(3)]^2+log6(18)/log2(6)[log6(3)]^2+log6(18)/log2(6)
(log6 2)^2+log6 3*log6 12
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2
(log6 3)^2+log6 2+log6 2log6 3=?
[(1-log6 3)^2+log6 2-log6 18]/log6 4
求值：（log6 2）²+log6 3*log 6 2+log6 3,应该怎么算?
(log6^4)(log6^18)+2(log6^3)^2
(log6 3)^2+log6 18乘以log6 2急求！！！！！！！！！！！！！！
log6 2=a log6 3=?
求值：[log6(3)]^2+log6(18)/log2(6)很着急.我已经知道演算的过程,想知道第三部为什么+[log6(2)]^2要有（乘）变为（加）,而且为什么要将它平方?[log6(3)]^2+log6(18)/log2(6)=[log6(3)]^2+log6(3^2 * 2)*[log6(2)]=[log6(
(log6(2))^2+log6(2)*log6(3)+log6(18)的值
{(1-log6 3)^2+log6 2*log6 18}/log6 4 等于多少,请写出就算过程,
（（1-log6（3））²+log6（2）*log6（18））/log6（4）
[（1-log6 3）²+log6 2×log6 18]/log6 4
2^log4(2-根号3)^2+3^log(2+根号3)^2[(1-log6(3)^2+log6(2)*log6(18)]/log6(4)[(1-log6(3))^2+log6(2)*log6(18)]/log6(4)
计算 (Log6 3)^2+【(log6 18)/(log2 6)]
计算[log6(3)]^2+log6(18)/log2(6)