y=(2x^2+4x+1)^12,dy/dx=?
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y=(2x^2+4x+1)^12,dy/dx=?y=(2x^2+4x+1)^12,dy/dx=?y=(2x^2+4x+1)^12,dy/dx=?=(48X+48)×(2X''2+4X+1)"11用复合函
y=(2x^2+4x+1)^12,dy/dx=?
y=(2x^2+4x+1)^12,dy/dx=?
y=(2x^2+4x+1)^12,dy/dx=?
=(48X+48) ×(2X'2+4X+1)"11
用复合函数求导
令u=(2x^2+4x+1)
dy/dx=dy/du*du/dx=12u^11*du/dx带入即可
令u=(2x^2+4x+1)
dy/dx=dy/du*du/dx=12u^11*du/dx
将u带入
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