y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 13:08:58
y=f[(x-1)/(x+1)],f''(x)=arctanx^2,求dy/dx,dyy=f[(x-1)/(x+1)],f''(x)=arctanx^2,求dy/dx,dyy=f[(x-1)/(x+1)]

y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy

y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
两边对x求导:
dy/dx=f'[(x-1)/(x+1)]*2/(x+1)^2
=arctan[(x-1)/(x+1)]^2*2/(x+1)^2
dy=f'[(x-1)/(x+1)]*2/(x+1)^2
=arctan[(x-1)/(x+1)]^2*2/(x+1)^2*dx