已知sin(α+π/6)=-5/13,3π/2<α<2π 则cosα=
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已知sin(α+π/6)=-5/13,3π/2<α<2π则cosα=已知sin(α+π/6)=-5/13,3π/2<α<2π则cosα=已知sin(α+π/6)=-5/13,3π/2<α<2π则cos
已知sin(α+π/6)=-5/13,3π/2<α<2π 则cosα=
已知sin(α+π/6)=-5/13,3π/2<α<2π 则cosα=
已知sin(α+π/6)=-5/13,3π/2<α<2π 则cosα=
二分之根号三sinα+二分之一cosα=—十三分之五
sinα的平方加cosα平方等于一 3π/2<α<2π cosα大于0
所以cos= 26分之(12倍根号3减去5)
26分之(12倍根号3减去5)
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