10.11
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10.1110.11 10.11⒑sin(π/4+α)=±√1-cos²(π/4+α)=±(2√2)/3∵0<α<π/2且cos(π/4+α)>0∴sin(π/4+α)=(2√2)
10.11
10.11
10.11
⒑sin(π/4+α)=±√1-cos²(π/4+α)=±(2√2)/3
∵0<α<π/2且cos(π/4+α)>0
∴sin(π/4+α)=(2√2)/3
sin(π/4-β/2)=±√1-cos²(π/4-β/2)=±√6/3
∵-π/2<β<0
∴0<-β<π/2
∴0<-β/2<π/4
则π/4<π/4-β/2<π/2
∴sin(π/4-β/2)=√6/3
cos(α+β/2)=cos[(π/4+α)-(π/4-β/2)]=cos(π/4+α)·cos(π/4-β/2)+sin(π/4+α)·sin(π/4-β/2)
=(1/3)×(√3/3)+[(2√2)/3]×(√6/3)=5√3/9
选C
⒒m·n=√3sinA·cosB+√3sinB·cosA=√3·sin(A+B)=1+cos(A+B)
∵A、B、C是△ABC的3个内角
∴A+B=π-C
∴√3sin(π-C)=1+cos(π-C)
√3sinC=1-cosC
√3sinC+cosC=1
2sin(C+π/6)=1
sin(C+π/6)=1/2
∴C=120°
选C