证明:设f(x)在x=0连续,且lim(x→0) (f(x)/x)=1,则必有f'(0)=1
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/21 18:08:10
证明:设f(x)在x=0连续,且lim(x→0)(f(x)/x)=1,则必有f''(0)=1证明:设f(x)在x=0连续,且lim(x→0)(f(x)/x)=1,则必有f''(0)=1证明:设f(x)在x
证明:设f(x)在x=0连续,且lim(x→0) (f(x)/x)=1,则必有f'(0)=1
证明:设f(x)在x=0连续,且lim(x→0) (f(x)/x)=1,则必有f'(0)=1
证明:设f(x)在x=0连续,且lim(x→0) (f(x)/x)=1,则必有f'(0)=1
因为lim(x→0) (f(x)/x)=1 所以,x与f(x)为等价无穷小:f(x) .x趋于0时,f(x)也趋于0
所以:f(0)=0
f'(0)= lim(x→0) [f(x)-f(0)]/(x-0)
= lim(x→0) f(x)/x
= 1
由lim(x→0)[f(x)/x]=1可知f(0)=0
f'(0)=lim(x→0){[f(x)-f(0)]/(x-0)}=lim(x→0)[f(x)/x]=1
设f(x)在x=0处连续,且lim(x趋于0)f(x)/x存在,证明,f(x)在x=0处可导
证明:设f(x)在x=0连续,且lim(x→0) (f(x)/x)=1,则必有f'(0)=1
设f(x)在x=0处连续,且lim(x趋于0)f(x)/x^2=1 ,证明函数f(x)在x=0处可导且取得极小值.
设f(x)在x=0处连续,且lim(x趋于0)f(x)/x^2=1 ,证明函数f(x)在x=0处可导且取得极小值.
设函数f(x)在(01]上连续,且极限lim->0+f(x)存在,证明函数f(x)在(0,1]上有界
设函数f(x)在(a,+∞ )上可导,且lim(x->+∞ )(f(x)+f'(x))=0,证明:lim(x->+∞ )f(x)=0
设f(x)在点x=o的某一邻域内具有连续的二阶导数,且lim(x->0)f(x)/x=0,证明:级数∑(n=1,∞)f(1/n)绝对收敛
设f(x)在x=0连续,且lim(x+sinx)/ln[f(x)+2]=1x趋近于0,则f'(0)?
设函数f(x)在(0,1]内连续可导,且lim(x趋向于0+)(√x)f`(x)存在,证明f(x)在(0,1]内一致连续我知道要把问题归结到证明lim(x趋向于0+)f(x)存在,如何由lim(x趋向于0+)(√x)f`(x)存在导出lim(x趋向于0+)f(x)存在,
设f(x)在[0,1]上有连续导数,且f(x)=f(0)=0.证明
设f'(x)在[a,b]上连续,证明:lim(λ→+∞)∫(a,b)f(x)cos(λx)dx=0
f(x)是定义在(0,+∞)上的连续可微函数,且lim(x->+∞)(f(x)+f ' (x))=0,证明lim(x->+∞)f(x)=0
几道高数题,高手给帮帮忙吧1.求lim(n→∞)sin^2(∏√(n^2+n))2.设f(x)在[a,+∞)上连续,且lim(x→+∞) f(x)存在,证明f(x)在[a,+∞)上有界.3.设f(x)在[0,n](n为自然数,n≥2)上连续,f(0)=f(n),证明存在ξ,ξ+1∈[
设f(x)在x=0的某邻域内连续,且lim x→0 [xf(x)-ln(1+x)]/x^2=2,求f(0),并证明f`(0)存在并求之答案第一步说由lim x→0 [xf(x)-ln(1+x)]/x^2=2及极限与无穷小的关系,解得f(x)=[(2+a)x^2+ln(1+x)]/x,其中lim x→0 a=0.这
设函数t(x)在点X=6处连续,且f(6)= -5 则 lim f(x)=?lim是 x->6
设limf(x)=A,且A>0,证明lim根号f(x)=根号A
急,定积分相关问题!1.设f(x)在[0,+∞)内连续,且lim(x→∞)f(x)=1.证明函数y=[e^(-x)]∫(0→x)(e^t)f(t)dt满足微分方程(dy/dx)+y=f(x),并求lim(x→∞)y(x).中的第二问答案“由条件lim(x→∞)f(x)=1,从而存在X0>0,当x
设函数f(x)在x=2处连续,且lim(x→2)f(x)/(x-2)(x→2)=3,求f'(2).