Lim[(x+1)(x^2+1)·……·(x^n+1)]/([nx)^n+1]^(n+1)/2

lim(1-x)^(2/x) x->0 Lim[(x+1)(x^2+1)·……·(x^n+1)]/([nx)^n+1]^(n+1)/2 lim((cos( √x))^(1/x)) x……0+ 洛必达求极限 limsinxlnx x趋近于0+,lim(2/π·arctanx)^x x趋近无穷大,lim(ln1(/x))^x x趋近0+,limlnx·ln(1+x) x趋近0+,lim(x^3+x^+x+1)^1/3-x x趋近无穷大,lim (e^x-e^sinx)/(x-sinx) x趋近0,lim(sinx/x)^(1/x^2)x趋近0,lim[1/e· (1/+x) lim（x+x^2+……+x^n-n）/(x-1) lim(1+x)(1+x^2)…[1+x^(2^n)],|x| 极限：lim(x->2)1/(x-2) lim(1-(5/x))^x-2 lim(x+e^2x)^(1/sinx) lim(x^2-1/x-1)=?(x趋近于无穷大)求极限··· lim(x->2) （x-2）·sin(1/2-x)为什么等于0? Lim(x>1) x-1/x^2+x-2.计算 lim x→1 x-1/x^2-x lim(x^2+1/x^2-2x)^x=? lim(x->无穷大){(2^x-3^x)/2}^(1/x) Lim [x^2/(x^2-1)]^x (x→∞) lim x->正无穷大 x ( sqrt(x^2+1)-x ) lim(x->0)((2-x)/(3-x))^1/x