把函数f(x)=2cos(2x+α)+1(0

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把函数f(x)=2cos(2x+α)+1(0把函数f(x)=2cos(2x+α)+1(0把函数f(x)=2cos(2x+α)+1(0f(x+π/3)=2cos(2(x+π/3)+α)+1=2cos(2

把函数f(x)=2cos(2x+α)+1(0
把函数f(x)=2cos(2x+α)+1(0

把函数f(x)=2cos(2x+α)+1(0
f(x+π/3)=2cos(2(x+π/3)+α)+1=2cos(2x+2π/3+α)+1
2cos(2*π/6+2π/3+α)+1 = 1
2cos(π+α)=0
cos(π+α)=cosα=0
0