lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 19:56:00
lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=
lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不
lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不
lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不
正确,当n→∞时,只看最高次项.
lim(n趋于无穷大)(5n^2+3n)/6n=∞对不
lim(n趋于无穷大)(5n^2+3n)/(6n^2+3)=5/6对不
lim(n趋于无穷大)(5n^2+3n)/(an^2+b)=多少
lim n趋于无穷大(1/n^2+3/n^2+.+2n-1/n^2
求lim n趋于无穷大((n+1)(n+2)(n+3)) / 5n的三次方 的极限
x趋于无穷大lim(1/n²+2/n²+...+n/n²)=
请老师回答问题,lim(n趋于无穷大)(1^n+2^n+3^n)1/n次方=?lim(x趋于无穷大)sin2x/x=?lim(x趋于0)sin(sinx)/x=?
lim[(2n^2+5n-1)/(3n^2-2n^2)+(3+5n)/(3n-1)]n趋于无穷大
lim[1/(n+1)+1/(n+2)+1/(n+3)+、、、1/(n+n)]当n趋于无穷大时的极限?
lim(n趋于无穷大)((根号下n^4+n+1)-n^2)(3n-4)=?答案是3/2求详解
lim(1/n+2/n+3/n+4/n+5/n+……+n/n)=lim(1/n)+lim(2/n)+……+lim(n/n)成立吗?(n趋近于无穷大)为什么不成立?
lim(n趋于无穷大),n^3*sin(1/n^3)lim(n趋于无穷大),n的3次方乘以sin的n的3次方分之一
高数 数列极限lim(1+ 2^n + 3^n)^(1/n) n趋于无穷大求极限
求极限问题lim(n+1/2n-1)^n,n趋于无穷大
证明:lim(1/3+1+1/3^2+1+...+1/3^n+1)存在,n趋于无穷大
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
高数求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢?
lim n趋于无穷大 1/(n^2+1)+2/(n^2+2).n/(n^2+n)的极限