log2[√(7/48)]+log2(12)-log2(√42)

log2[√(7/48)]+log2(12)-log2(√42) log2 SQR(7/48)+log2 12 -1/2log2 48 log2 SQR(7/48)+log2 12 -1/2log2 42 化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3 求值：log2√(7/48)+log2(12)-1/2log2(42)-1 这道题我算来算去算不对 计算log2 √(48/7)-log2 12+(1/2)log2 42-1 Log2√（7/48） +log2 12 -（1/2）log2 42要详细点的额 log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙! 1/2log2(7/48)+log2 12-1/2log2 42log2 的2 在g的右下脚 log2（√1/48）+log2 12-1/2log2 （24）-1/3 log2底√1/48+log2底12-1/2log2底24等于? log2(根号下7/48)+log2(12)-1/2log2(42)-1=? log2根号7/48+log2^12-1/2log2^42-1= log2 √7/24+log2 12-log442 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ log2(log2 求化简log2根号下48分之7+log2 12-log2 42 log2为底数根号7/48为真数+log2为底数12为真数-1/2log2为底数42为真数=?