若数列an 满足a(1+n)=1-(1/an) 且a1=2 则a2009=?

已知数列{an}满足a(n+1)=an+n,a1=1,则an= 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 周期性数列问题i已知数列｛an}满足a(n+1)=2an (0 若数列{an}满足a1>0,且a(n+1)=(n/n+1)乘以an,则数列{an}是 递增数列,递减数列 常数列 摆动数列求详解 数列｛an｝满足lim(an+1-an)=a,证明liman/n=a 【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通...【高考】若数列{an}满足,a1=1,且a(n+1)=an/1+an,证明,数列｛1/an｝为等差数列,并求出数列{an}的通项公式 若数列{An}满足A1=2,nA(n+1)-(n+1)An=2,则数列{An}的通项公式A后面的n都是下标 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 已知数列{an}满足a(n+1)=an+lg2,a1=1,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a（n+1）=2^n·an,则数列an的通项公式? 已知数列an满足an=2a(n-1)+2^n-1,a4=81,若数列{(an+p)/2}为等差数列,求p 已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式 数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式 数列｛an｝满足a1=1,an=a(n-1)+1/(n2-n),求数列的通项公式 若数列{an}满足条件log2(1+an)=n,求数列{an}通项公式an= 求一道很简单的数列题数列｛a｝满足an=（n^2+n+1)/3求an+1 已知数列an满足:a1=1,an-a(n-1)=n n大于等于2 求an