若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/10/03 17:01:39
若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a
若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?
若数列an满足a1=1,an+1=2^nan...
若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?
若数列an满足a1=1,an+1=2^nan...若数列an满足a1=1,a(n+1)=2^n·an,则数列an的通项公式?
a(n+1)/an=2^n
于是
an/a(n-1)=2^(n-1)
a(n-1)/a(n-2)=2^(n-2)
...
a2/a1=2^1
相乘有
an/a1=2^(n-1)*2^(n-2)*...*2^1=2^((n-1)+(n-2)+...+1)=2^(n(n-1)/2)
于是an=a1*2^(n(n-1)/2)=2^(n(n-1)/2)
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列an满足a1=1/3,Sn=n(2n-1)an,求an
数列{an}满足a1=2,a(n+1)=2an+n+2,求an
若数列【an】满足a1等于1,An+1=2an+3n,则数列的项A5
数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an
已知数列{an}满足a1=1,an+1·an=2^n 则s2012
已知数列{an}满足a1=1/2,sn=n^2an,求通项an
数列[An]满足a1=2,a(n+1)=3an-2 求an
已知数列{an},满足a1=1/2,Sn=n²×an,求an
已知数列an满足a1=1/2 sn=n平方×an 求an
数列an满足a1=0,An+1=an+2n求a2009
已知数列An满足 A1=1/2 Sn=N²An 求An
已知数列an满足a1=1 Sn=2an+n 求an
数列an满足a1=1/2,a1+a2+a3……an=n^2an,则an