数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1a/b=?题目如上我做到。a+2b=1????
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数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1a/b=?题目如上我做到。a+2b=1????数列的极限高
数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1a/b=?题目如上我做到。a+2b=1????
数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1
lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1
a/b=?
题目如上
我做到。a+2b=1????
数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1a/b=?题目如上我做到。a+2b=1????
lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1,
括号里分子分母同时除以n:lim(2bn+4+an-2+(1/n)/ (b+2/n))=1
当n趋于无穷时,1/n=2/n=0;要是方程成立,则:2b+a=0,(4-2)/b=1
因此得:b=2,a=-4.
如果题目没错,那就是如图所示 结果应该是-1
发详细题目图片到我QQ邮箱[email protected]
(若n是趋于无穷大,则)由题目有: a + 2b = 0 , 且有 2n = bn , 所以有 b = 2 , a = --4,
即有a / b = --2.
数列的极限高中lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1lim(2bn^2+4n+an^2-2n+1)/(bn+2)=1a/b=?题目如上我做到。a+2b=1????
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