数列极限 lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
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数列极限lim{[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?数列极限lim{[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
数列极限 lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
数列极限
lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
数列极限 lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5
lim {[(3n^2+cn+1)-4n(an^2+bn)]/(an^2+bn)}=5
lim {[-4an^3+(3-4b)n^2+cn+1]/(an^2+bn)}=5
所以
-4a=0
3-4b=0
c/b=5
解得:
a=0
b=3/4
c=15/4
a=0
b=3/4
c=15/4
此题有问题
因为lim [(3n^2+cn+1)/(an^2+bn)]=3/a
而 lim (-4n)不存在
数列极限 lim {[(3n^2+cn+1)/(an^2+bn)]-4n}=5,则常数a=?b=?c=?
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