cos(19π/6)+tan(16π/3)=?

cos(19π/6)+tan(16π/3)=? Sinπ/3Tanπ/3+tanπ/6COSπ/6－Tanπ/4COSπ/2 cos（6分之19π）tan（-3分之16π）化成π的形式, sin29π/6+cos(-29π/3)+tan(-25/4) tan(-2010°)+cos(-79π/6) cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?. cosπ|3-tanπ|4+3|4tan²π|6+cos²π|6-sinπ|4 【sin330°*tan(-13π/3)】/【cos(-19π/6)*cos690°】 [sin330°-tan(-13π/3）]/[cos(-19π/6）-cos690°] 求值:2cosπ/2-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6+sin3π/2 -1/4cosπ 求证：[tan（2π-α）cos（3π/2-α)cos(6π-α)]/[sin(α+3π/2)cos(α+3π/2)]=-tanα 若α∈(0,π/6) 比较tan(sinα),tan(cosα),tan(tanα)的大小 求证tan(2π-a)cos(3π/2 -a)cos(6π -a) / sin(a+3π/2)cos(a+3π/2) = -tan求证tan(2π-a)cos(3π/2 -a)cos(6π -a) / sin(a+3π/2)cos(a+3π/2) = -tan 化简（tan@+1比tan@）cos@的平方等于 （用特值法）例三分之π1.tan@ 2.sin@3cos@ 4.1比tan@ 计算（1）cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6[tan(-150°)cos（-210°）cos420°]/cot(-600°)sin（-1050°）cos25/6π+cos25/3π+tan(-25/4π)5sinπ/2+2cos0-3sin3/2π+10cosπt 计算cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6cosπ/3-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6[tan(-150°)cos（-210°）cos420°]/cot(-600°)sin（-1050°）cos25/6π+cos25/3π+tan(-25/4π)5sinπ/2+2cos0-3sin3/2π+10cosπtan10°t sin(x+π/3)+（tanπ/6）cos(x+π/3) 化简 sin(x+π/3)+（tanπ/6）cos(x+π/3) 化简 计算2cosπ/2-tanπ/4+3/4tan²π/6-sinπ/6+cos²π/6+sin3π/2同上 写出过程