3x-2y+z=3 2x+y-z=4 4x+3y+2z=-10
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3x-2y+z=32x+y-z=44x+3y+2z=-103x-2y+z=32x+y-z=44x+3y+2z=-103x-2y+z=32x+y-z=44x+3y+2z=-103x-2y+z=3(1)2
3x-2y+z=3 2x+y-z=4 4x+3y+2z=-10
3x-2y+z=3 2x+y-z=4 4x+3y+2z=-10
3x-2y+z=3 2x+y-z=4 4x+3y+2z=-10
3x-2y+z=3(1) 2x+y-z=4(2)4x+3y+2z=-10(3),
由(2)得z=2x+y-4(4),
将(4)分别代入(1)(3)式得3x-2y+(2x+y-4)=3 化简得5x-y=7(5),
4x+3y+2(2x+y-4)=-10化简得8x+5y=-2(6),
由(5)(6)解得x=1 ,y=-2
代入(4)得z=-4
所以原三元一次方程组的解为x=1 y=-2 z=-4
3x-2y+z=3 (1)
2x+y-z=4 (2)
4x+3y+2z=-10 (3)
(1)+(2)*2
7x-z=11
(2)*3-(3)
2x-5z=22
z=7x-11
2x-35x+55=22
x=1
z=-4
y=-2
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
x/2=y/3=z/4,则x+2y-z/z=?
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
x+y=5 2x+3y-z=9 x-y+z=4
{2x+y=10 {x-y+z=4 {3x-y-z=0
解方程:{2x+3y+z=7,x+y+z=4,3x+y-z=-4{2x+3y+z=7,x+y+z=4,3x+y-z=-4要过程
x,y,z满足x+y+z=3,x^2+y^2+z^2=29,x^3+y^3+z^3=45,求x,y,z,x^4+y^4+z^4等于几
三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6
x+y/2=z+x/3+y=z/4,...x+y+z=27.解方程组.X+Y/2=Z+X/3=Y+Z/4,X+Y+Z=27.解方程
解方程 x+y+z=0 4x+2y+z=3 9x-3y+z=28解方程x+y+z=04x+2y+z=39x-3y+z=28