2x-y=10 【（x²+y²）-（x-y)²+2y（x-y）】÷4y

x²+y²-2x-6y+10=0 求分式x²-y²/xy 已知x²y²+x²+y²=10xy-16 求x,y ( x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0 )求出x,y 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y x²-4y² x+2y---------- ÷ --------分数线x²+2xy+y² x²+xyx²-4y² x+2y----------÷--------分数线x²+2xy+y² x²+xy(x+2y)(x-2y)x(x+y)=----------------(x+y)(x+y)(x+2y)(x-y)x=------(x+y)这样对了吗? 2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 已知x²-4x+y²-10y+29=0.求x²y²+2x³y²+[x²]²y²的值. 已知2x-y=10 【（x²+y²）-（x-y)²+2y（x-y）】÷4y 过程 2x-y=10 【（x²+y²）-（x-y)²+2y（x-y）】÷4y 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值 x²-2x+y²+6y+10=0,求—9(x+y)²+(3x-2y)(2y+3x)的值 x²-y²=1｛(x-y)²-2(x-y-2)=7 x²+y²-10x-10y=0 ,x²+y²-6x+2y-40=0请帮忙算出这组方程的解. 求两圆C1:x²+y²-10x-10y=0,C2：x²+y²+6x+2y-40=0公共弦长 已知x²+4x+y²-10y+29=0 求【x+2y】÷【x²-2y²】的值 化简再求值[(x²+y²）²-4x²y²]÷(x²-y²）其实,x=2,y=2/3.