{5x-2y+z=12 {4x+3y+z=1 {7x+4y+z=2(解,要有过程)详细,我会提高悬赏,谢谢谢!
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{5x-2y+z=12{4x+3y+z=1{7x+4y+z=2(解,要有过程)详细,我会提高悬赏,谢谢谢!{5x-2y+z=12{4x+3y+z=1{7x+4y+z=2(解,要有过程)详细,我会提高悬
{5x-2y+z=12 {4x+3y+z=1 {7x+4y+z=2(解,要有过程)详细,我会提高悬赏,谢谢谢!
{5x-2y+z=12 {4x+3y+z=1 {7x+4y+z=2(解,要有过程)
详细,我会提高悬赏,谢谢谢!
{5x-2y+z=12 {4x+3y+z=1 {7x+4y+z=2(解,要有过程)详细,我会提高悬赏,谢谢谢!
5x-2y+z=12 …………①
4x+3y+z=1…………②
7x+4y+z=2…………③
①-②:x-5y=11…………④
①-③:-2x-6y=10…………⑤
④*2+⑤:-16y=32
所以:y=-2
代入④:x=1
所以:z=3
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
x+2y-z=-5 x+y+2z=-1 3x+4y-2z=-12x+2y-z=3 2x+y+3z=0 4x+z=-4
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
三元一次方程组解法 4x+y-z=12 x+y+z=26 3x+2y+z=-5 x-y=1 x-y+5z=1 2x-y+z=18 急 急、、、、、、、、、、
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
4X+9Z=12 {3Y-2Z=17X+5Z=4又4分之33X-Y+2Z=3{2X+Y-3Z=11X+Y+Z=66
{x+y+z=12 x+2y+5z=22 x=4y
x+y=5 2x+3y-z=9 x-y+z=4
方程组3x+y-4z=1 2x-y-2z=6 5x+3y-3z= --1/2{负二分之一} x=?y=?z=?3x+2y+z=13 x+y+2z=7 2x+3y-z=12 x=?y=?z=?
4x+2y+z=5,4x-2y+z=1,z=-15x+2y+z=12,4x+3y+z=13,z=3
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-6=0③x/3=y/2 y/4=z/5 x+y+z=60三元一次方程
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1