求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)
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求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)求值sin120
求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)
求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)
求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)
sin120°+cos180°+tan45°-cos(-330°)+sin(-210°) =3/4+(-1)+1-3/4+1/2 =1/2
求值sin120°+cos180°+tan45°-cos(-330°)+sin(-210°)
sin120°=?
sin120°的值为
sin120°等于cos多少
sin120°、sin210°分别是多少?
sin120°和sin60相等吗?
cos180°为什么等于-1呢?
关于sin120°的值sin120°的值怎么理解(图也看不懂)
cos180°为什莫等于-1求详解~
化简:-p²cos180°+qsin9°-2pqcos0°化简-p²cos180°+qsin9°-2pqcos0°
sin2120°+cos180°+tan45°-cos2(-330°)+sin(-210°) 最好快点、、sin2120°+cos180°+tan45°-cos2(-330°)+sin(-210°)
sin1°+sin2°+...+sin89°+sin90°+cos91°+cos92°+...+cos179°+cos180°
sin平方120°+cos180°+tan45°-cos平方(-330°)+sin(-210°)
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
计算3cos90°-2sin0°+tan0°-cos180°+tan180°
cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
cos1°+cos2°+cos3°+...+cos180°的值为?
cos180°,sin180°,tan180°分别等于多少?怎样求得?