cos1°+cos2°+cos3°+...+cos180°的值为?
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cos1°+cos2°+cos3°+...+cos180°的值为?cos1°+cos2°+cos3°+...+cos180°的值为?cos1°+cos2°+cos3°+...+cos180°的值为?c
cos1°+cos2°+cos3°+...+cos180°的值为?
cos1°+cos2°+cos3°+...+cos180°的值为?
cos1°+cos2°+cos3°+...+cos180°的值为?
cosα=-cos(180°-α)
cos1°+cos2°+cos3°+...+cos180°=0
cos1°+cos2°+cos3°.+co180°=?
cos1°+cos2°+cos3°+.+cos360°
cos1°+cos2°+cos3°+...+cos179°化简
cos1°+cos2°+cos3°+.+cos359°等于多少.
cos1°²+cos2°²+cos3°²+cos4°²...+cos89°²=?
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
cos1°+cos2°+cos3°+...+cos²89°过程和答案!速度啊 多谢!
cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
cos1°+cos2°+cos3°+...+cos180°的值为?
Cos1°+cos2°+cos3°+……cos89°=
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
cos1°×cos1°+cos2°×cos2°+……+cosn
(sin1°-cos1°)(sin2°-cos2°)(sin3°-cos3°)……(sin89°-cos89°)=一定要告诉我原因啊 谢谢最后得0.
cos1°的二次方+cos2°的二次方+cos3°的二次方+……cos89°的二次方=
比大小cos1,cos2,cos3,cos4
cos1 cos2 cos3 cos4 的大小关系
cos1/7*cos2/7*cos3/7=?